1010: [编程入门]利润计算

解题思路暴力解决

注意事项:

参考代码:

#include<stdio.h>

int main()

{

float x,y;

scanf("%f",&x);

if(x<=100000)

y=x*0.1;

else if(x<=200000)

y=(x-100000)*0.075+100000*0.1;

else if(x<=400000)

y=(x-200000)*0.05+100000*0.1+100000*0.075;

else if(x<=600000)

y=(x-400000)*0.03+100000*0.1+100000*0.075+200000*0.05;

else if(x<=1000000)

y=(x-600000)*0.015+100000*0.1+100000*0.075+200000*0.05+200000*0.03;

else

y=(x-1000000)*0.01+100000*0.1+100000*0.075+200000*0.05+200000*0.03+400000*0.015;

printf("%.0f",y);

return 0;

}