[编程入门]利润计算-最简单无脑的题解(C语言代码)

解题思路:

注意事项:

参考代码:

#include <stdio.h>

int main()

{

    int a,t;

    scanf("%d",&a);

    if(a<=100000)

t=a*0.1;

    printf("%d",t);

    if(a>100000&&a<=200000){

t=100000*0.1+(a-100000)*0.075;

    printf("%d",t);}

    if(a>200000&&a<=400000){

t=100000*0.1+100000*0.075+(a-200000)*0.05;

    printf("%d",t);}

    if(a>400000&&a<=600000){

t=100000*0.1+100000*0.075+200000*0.05+(a-400000)*0.03;

    printf("%d",t);}

    if(a>600000&&a<=1000000){

t=100000*0.1+100000*0.075+200000*0.05+200000*0.03+(a-600000)*0.015;

    printf("%d",t);}

    if(a>1000000){

t=100000*0.1+100000*0.075+200000*0.05+200000*0.03+400000*0.015+(a-1000000)*0.03;

    printf("%d",t);}

return 0;

}