鸡兔同笼-题解（C++代码）

解题思路:

注意事项:

参考代码:

#include <iostream>

using namespace std;

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char** argv) 

{

int x,y,m,n,l;

while(cin>>n>>m)

{

x=(4*n-m)/2;

y=n-x;

if(x<0||y<0||(4*n-m)%2!=0)

{

cout<<"No answer"<<endl;

}

else

{

cout<<x<<" "<<y<<endl;

}

}

return 0;

}