[编程入门]自定义函数之数字后移-题解（C语言代码）

解题思路:

注意事项:

参考代码:

#include <stdio.h>                                       

int exchange(int a[ ],int n,int b[ ],int m);     

int main( )                                                     

{                                                                     

     int n ,  m, a[100], i , b[100];                      

     scanf("%d",&n);                                        

     for(i = 0;i < n;i++)                                    

     {                                                                

          scanf("%d",&a[i]);                                

     }                                                                

     scanf("%d",&m);                                       

     exchange(a,n,b,m);                                   

     for(i=0;i<n;i++)                                        

         printf("%d ",b[i]);                                  

     return 0;                                                   

}                                                                     

int exchange(int a[ ],int n,int b [ ],int m)     

{                                                                     

     int t, i, j=0;                                                

     for(i=0;i<n;i++)                                        

     {                                                                 

         if(i<m)                                                   

         {                                                             

              b[i]=a[n-m+i];                                  

         }                                                              

         else                                                        

         {                                                              

             b[i]=a[j];                                              

             j++;                                                     

         }                                                              

     }                                                                  

     return 0;                                                     

}