[编程入门]数字的处理与判断-题解（C语言代码）(if语句 简单易懂)

解题思路:if语句判断

注意事项:萌新路过，大佬勿喷

参考代码:

#include<stdio.h>

int main()

{

int a,i,n1,n2,n3,n4,n5;

scanf("%d",&a);

if(a%10==a)

{

i=1;

n1=a;

printf("%d\n",i);

printf("%d\n",n1);

printf("%d",n1);

}

else if(a%100==a)

{

i=2;

n1=a%10;

n2=a/10;

printf("%d\n",i);

printf("%d %d\n",n2,n1);

printf("%d%d",n1,n2);

}

else if(a%1000==a)

{

i=3;

n1=a%10;

n2=(a/10)%10;

n3=(a/100)%10;

printf("%d\n",i);

printf("%d %d %d\n",n3,n2,n1);

printf("%d%d%d",n1,n2,n3);

}

else if(a%10000==a)

{

i=4;

n1=a%10;

n2=(a/10)%10;

n3=(a/100)%10;

n4=(a/1000)%10;

printf("%d\n",i);

printf("%d %d %d %d\n",n4,n3,n2,n1);

printf("%d%d%d%d",n1,n2,n3,n4);

}

else if(a%100000==a)

{

i=5;

n1=a%10;

n2=(a/10)%10;

n3=(a/100)%10;

n4=(a/1000)%10;

n5=(a/10000)%10;

printf("%d\n",i);

printf("%d %d %d %d %d\n",n5,n4,n3,n2,n1);

printf("%d%d%d%d%d",n1,n2,n3,n4,n5);

}

}