[编程入门]自定义函数之字符类型统计-题解（C语言代码）

解题思路:

注意事项:

参考代码:

#include <stdio.h>
#include <string.h>
int main()
{
    char str[1000];
    gets(str);
    count(str);
}

int count(char str[1000])
{
    int number, space, letter, others, n, i;
    n = strlen(str);
    number = 0;
    space = 0;
    letter = 0;
    others = 0;
    for(i = 0 ; i < n ; i ++)
    {
        if('a' <= str[i] && str[i] <='z' || 'A' <= str[i] && str[i] <= 'Z')
        {
            letter ++;
        }
        else if('0' <= str[i] && str[i] <= '9')
        {
            number ++;
        }
        else if(str[i]==' ')
        {
            space ++;    
        }
        else
        {
            others++;
        }
    }
    printf("%d %d %d %d",letter, number, space, others);
}