[编程入门]结构体之时间设计-题解（C语言代码）

参考代码:

#include <stdio.h>
#include <stdlib.h>
#include<string.h>
struct time{
int year;
int month;
int day;
};
int main()
{
    struct time time1;
    scanf("%d%d%d",&time1.year,&time1.month,&time1.day);
    if(time1.year%4==0)
    {
        switch(time1.month)
        {
            case 1:printf("%d",time1.day);break;
            case 2:printf("%d",time1.day+31);break;
            case 3:printf("%d",time1.day+31+29);break;
            case 4:printf("%d",time1.day+31+29+31);break;
            case 5:printf("%d",time1.day+31+29+31+30);break;
            case 6:printf("%d",time1.day+31+29+31+30+31);break;
            case 7:printf("%d",time1.day+31+29+31+30+31+30);break;
            case 8:printf("%d",time1.day+31+29+31+30+31+30+31);break;
            case 9:printf("%d",time1.day+31+29+31+30+31+30+31+31);break;
            case 10:printf("%d",time1.day+31+29+31+30+31+30+31+31+30);break;
            case 11:printf("%d",time1.day+31+29+31+30+31+30+31+31+30+31);break;
            case 12:printf("%d",time1.day+31+29+31+30+31+30+31+31+30+31+30);break;

           default:break;

        }
    }
    else
    {
        switch(time1.month)
        {
            case 1:printf("%d",time1.day);break;
            case 2:printf("%d",time1.day+31);break;
            case 3:printf("%d",time1.day+31+28);break;
            case 4:printf("%d",time1.day+31+28+31);break;
            case 5:printf("%d",time1.day+31+28+31+30);break;
            case 6:printf("%d",time1.day+31+28+31+30+31);break;
            case 7:printf("%d",time1.day+31+28+31+30+31+30);break;
            case 8:printf("%d",time1.day+31+28+31+30+31+30+31);break;
            case 9:printf("%d",time1.day+31+28+31+30+31+30+31+31);break;
            case 10:printf("%d",time1.day+31+28+31+30+31+30+31+31+30);break;
            case 11:printf("%d",time1.day+31+28+31+30+31+30+31+31+30+31);break;
            case 12:printf("%d",time1.day+31+28+31+30+31+30+31+31+30+31+30);break;

            default:break;

       }

    }
    return 0;
}