[编程入门]数字的处理与判断-题解（~~~运用简单的if语句解题~~~）

解题思路:if语句

注意事项:

参考代码:

#include<stdio.h>

int main()

{

    int a;

    scanf("%d",&a);

    if(a<10)    

    {

        printf("1\n");

        printf(" %d\n",a);

        printf("%d",a);

    }

    if(a>=10&&a<100)

    {

        printf("2\n");

        printf("%d %d\n",a/10,a%10);

        printf("%d%d",a%10,a/10);

    }

    if(a>=100&&a<1000)

    {

        printf("3\n");

        printf("%d %d %d\n",a/100,a/10%10,a%10);

        printf("%d%d%d",a%10,a/10%10,a/100);

    }

    if(a>=1000&&a<10000)

    {

        printf("4\n");

        printf("%d %d %d %d\n",a/1000,a/100%10,a/10%10,a%10);

        printf("%d%d%d%d",a%10,a/10%10,a/100%10,a/1000); 

    }

    if(a>=10000&&a<100000)

    {

        printf("5\n");

        printf("%d %d %d %d %d\n",a/10000,a/1000%10,a/100%10,a/10%10,a%10);

        printf("%d%d%d%d%d",a%10,a/10%10,a/100%10,a/1000%10,a/10000);

    }

}