写的有点憨,看看就好了
import java.util.Scanner; public class 打印十字图 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int len = 4 * (n - 1) + 9; int[][] a = new int[len][len]; for (int i = len / 2 - 2; i < len / 2 + 3; i++) { a[i][len / 2] = 1; a[len / 2][i] = 1; } for (int k = 0; k < n; k++) { for (int i = 0; i < a.length; i++) { for (int j = 0; j < a[i].length; j++) { if ((i == (k * 2) || i == len - 1 - (k * 2)) && j >= 2 + (k * 2) && j < len - 2 - (k * 2)) { a[i][j] = 1; } if ((j == (k * 2) || j == len - 1 - (k * 2)) && i >= 2 + (k * 2) && i < len - 2 - (k * 2)) { a[i][j] = 1; } if ((i == 2 + (k * 2) || i == len - 3 - (k * 2)) && j == 2 + (k * 2)) { a[i][j] = 1; a[i][j - 1] = 1; if (i == 2 + (k * 2)) { a[i - 1][j] = 1; } if (i == len - 3 - (k * 2)) { a[i + 1][j] = 1; } } if (j == len - 3 - (k * 2) && (i == len - 3 - (k * 2) || i == 2 + (k * 2))) { a[i][j] = 1; a[i][j] = 1; a[i][j + 1] = 1; if (i == 2 + (k * 2)) { a[i - 1][j] = 1; } if (i == len - 3 - (k * 2)) { a[i + 1][j] = 1; } } } } } for (int i = 0; i < a.length; i++) { for (int j = 0; j < a[i].length; j++) { if (a[i][j] == 1) { System.out.print("$"); } else { System.out.print("."); } } System.out.println(); } } }
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龚秋志 2021-03-09 09:58:59 |
代码忘记简化了,不过这种打印图形的题目营养性不高,看看就好了。