1017完数的判断

#include<stdio.h>

int main()

{

int i,j,k,sum=0,N,a[200000],num=1;

scanf("%d",&N);

for(i=1;i<=N;i++)

{

for(j=1;j<i;j++)

{

if(i%j==0){

a[num++]=j;

sum+=j;

}

if((sum==i)&&(j==i-1))

{

printf("%d its factors are ",i);

for(k=1;k<num;k++)

if(k==num-1)

printf("%d\n",a[k]);

    else printf("%d ",a[k]);

}

}sum=0;num=1;

}return 0;

}