[编程入门]自定义函数之字符类型统计-题解(C语言代码)

#include<stdio.h>
#include<string.h>
void fun(char a[])
{
    int i,number=0,word=0,space=0,other=0;
    for(i=0;i<strlen(a);i++)
    {
        if(a[i]>='A'&&a[i]<='Z'||a[i]>='a'&&a[i]<='z')
            word++;
        else if(a[i]>='0'&&a[i]<='9')
            number++;
        else if(a[i]==' ')
            space++;
        else
            other++;
    }
    printf("%d %d %d %d",word,number,space,other);
}
int main()
{
    char a[100];
    gets(a);
    fun(a);
    return 0;
}