蓝桥杯算法提高VIP-企业奖金发放-题解(C++代码)

本题的switch语句解法，比较麻烦可以了解一下

#include<iostream>
#include<iomanip>
using namespace std;
int main() {
    cout<<fixed<<setprecision(2);
    double profit=0;
    double bonus,sum=0;
    int c;
    cin>>profit;
    c=profit/100000;
    if(c>=0)
        switch(c) {
            case 0:
                bonus=profit*0.1;
                cout<<bonus<<endl;
                break;
            case 1:
                bonus=10*10000*0.1+(profit-10*10000)*0.075;
                cout<<bonus<<endl;
                break;
            case 2:
                bonus=10*10000*0.175+(profit-20*10000)*0.05;
                cout<<bonus<<endl;
                break;
            case 3:
                bonus=10*10000*0.175+(profit-20*10000)*0.05;
                cout<<bonus<<endl;
                break;
            case 4:
                bonus=10*10000*0.175+20*10000*0.05+(profit-40*10000)*0.03;
                cout<<bonus<<endl;
                break;
            case 5:
                bonus=10*10000*0.175+20*10000*0.05+(profit-40*10000)*0.03;
                cout<<bonus<<endl;
                break;
            case 6:
                bonus=10*10000*0.175+20*10000*0.05+20*10000*0.03+(profit-60*10000)*0.015;
                cout<<bonus<<endl;
                break;
            case 7:
                bonus=10*10000*0.175+20*10000*0.05+20*10000*0.03+(profit-60*10000)*0.015;
                cout<<bonus<<endl;
                break;
            case 8:
                bonus=10*10000*0.175+20*10000*0.05+20*10000*0.03+(profit-60*10000)*0.015;
                cout<<bonus<<endl;
                break;
            case 9:
                bonus=10*10000*0.175+20*10000*0.05+20*10000*0.03+(profit-60*10000)*0.015;
                cout<<bonus<<endl;
                break;
            case 10:
                bonus=10*10000*0.175+20*10000*0.05+20*10000*0.03+40*10000*0.015+(profit-100*10000)*0.01;
                cout<<bonus<<endl;
                break;
            default:
                bonus=10*10000*0.175+20*10000*0.05+20*10000*0.03+40*10000*0.015+(profit-100*10000)*0.01;
                cout<<bonus<<endl;
                break;
        }
    return 0;
}