C语言程序设计教程（第三版）课后习题5.8 （C语言代码）

解题思路:





注意事项:





参考代码:#include<stdio.h>
int main()
{
    int a,t;
    scanf("%d",&a);
    if(a<=100000)
    t = a*0.1;
    else if(100000<a<=200000)
    t = (a-100000)*0.075+100000*0.1;
    else if(20000<a<=400000)
    t = (a-200000)*0.05+100000*0.1+200000*0.075;
    else if(400000<a<=600000)
    t = (a-500000)*0.03+100000*0.1+100000*0.075+200000*0.05;
    else if(600000<a<=1000000)
    t = (a-600000)*0.015+100000*0.1+100000*0.075+200000*0.05+200000*0.03;
    else
    t = (a-1000000)*0.01+100000*0.1+100000*0.075+200000*0.05+200000*0.03+400000*0.015;
    printf("%d",t);
    return 0;
}