解题思路:先用字符数组储存好时h和分m的对应输出。h>=0&&h<=23;m>=0&&m<=59;
再根据要求先考虑时,用选择语句解决;再考虑分,这里注意,例如0:30是zero thirty而不是zero thirty zero
注意事项:如上
参考代码:
#include<stdio.h>
#include<string.h>
int main()
{
int h,m;
int ge,shi;
char a[21][20]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty"};
char b[6][20]={"","","twenty","thirty","forty","fifty"};
char c[20]="o'clock";
scanf("%d%d",&h,&m);
if(h<=20)
printf("%s ",a[h]);
else
{
ge=h/1%10;
shi=h/10%10;
printf("%s ",b[shi]);
printf("%s ",a[ge]);
}
if(m==0)
printf("%s",c);
else
{
if(m<=20)
printf("%s",a[m]);
else
{
shi=m/10%10;
printf("%s",b[shi]);
ge=m/1%10;
if(ge!=0)
{
printf(" ");
printf("%s",a[ge]);
}
}
}
return 0;
}
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