蓝桥杯打印十字图 （C++代码）##思路简单，易理解##

解题思路:
简化图形为其四分之一图案，然后拼接。

比如 n = 3时，

注意事项:
边界处理

参考代码:

#include<iostream> 

using namespace std;

char quarter[61][61];

int main()

{

int n;

while (cin >> n)

{

//初始化

for (int i = 0; i < 2*n+3; i++)

{

for (int j = 0; j < 2*n+3; j++)

{

quarter[i][j] = '$';

}

}

//设计右下角的四分之一图案

for (int i = 3; i < 2*n+3; i = i+2)

{

for (int j = 0; j < i-1; j++)

{

quarter[i][j] = '.';

quarter[j][i] = '.';

}

}

for (int i = 1; i < 2*n+3; i = i+2)

{

quarter[i][i] = '.';

quarter[i][i+1] = '.';

quarter[i+1][i] = '.';

}

quarter[2*n+2][2*n+2] = '.';

//拼接打印

for (int i = 2*n+3-1; i >= 0; i--)

{

for (int j = 2*n+3-1; j >= 0; j--)

{

cout << quarter[i][j];

}

for (int j = 1; j < 2*n+3; j++)

{

cout << quarter[i][j];

}

cout << endl;

}

for (int i = 1; i < 2*n+3; i++)

{

for (int j = 2*n+3-1; j >= 0; j--)

{

cout << quarter[i][j];

}

for (int j = 1; j < 2*n+3; j++)

{

cout << quarter[i][j];

}

cout << endl;

}

}

return 0;

}