【偶数求和】 （C语言代码）

#include <stdio.h>
int main()
{
     int i,n,m,s,t;
     int a[10000];  
   
     a[0]=0;
     for(i=1;i<10000;i++)
          a[i]=a[i-1]+2;

     while(scanf("%d%d",&n,&m)!=EOF)
     {       
              s=0;t=0;

              for(i=1;i<=n;i++)
              {
                   s=s+a[i];
                   t++;

                   if(i==n)
                   {
                      printf("%d\n",s/t);
                      s=0;t=0;
                      break;
                    }

                   if(t==m)
                   {
                      printf("%d ",s/t);
                      s=0;t=0;
                    }
               }
     }

     return 0;
}

解题思路:





注意事项:





参考代码: