字符串的输入输出处理 （C++代码）

#pragma warning(disable:4996)
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cctype>
#include<cmath>
int main(void) {
	char ch[1001];
	int n, count = 1;

	scanf("%d", &n);
	getchar();
	while (gets(ch)) {
		if (count <= n){
			puts(ch);
			printf("\n");
		}
		else {
			int len = strlen(ch);
			int t = 0, i, j;
			for (i = 0; i <= len; i++) {
				if (ch[i] == ' ' || ch[i] == '\0') {
					for (j = t; j < i; j++){
						printf("%c", ch[j]);
						if (j == i - 1)
							printf("\n\n");
					}
					j++;
					t = j;
				}
				
			}
		}
		count++;
	}

	return 0;
}

哦，不对 是这种。最开始的那个思路

#pragma warning(disable:4996)
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cctype>
#include<cmath>
int main(void) {
	char ch[1001];
	int n, count = 1;

	scanf("%d", &n);
	getchar();
	while (gets(ch)) {
		if (count <= n){
			puts(ch);
			printf("\n");
		}	
		else {
			int len = strlen(ch);
			int i;
			for (i = 0; i < len; i++) {
				if (ch[i] == ' '){
					printf("\n\n");
				}
				else{
					printf("%c", ch[i]);
				}
			}
			printf("\n\n");
		}
		count++;
	}

	return 0;
}
刚写出来了 谢谢大家咯