破解简单密码 （C语言代码）

解题思路:
遍历每个元素  转换成对应密码
注意事项:
最后Z的处理需要单独拿出
参考代码:

#include <stdio.h>

#include<string.h>

int main(){

int i,l;

char a[101];

while(scanf("%s",a)!=EOF)

{

l=strlen(a);

for(i=0;i<=l;i++)

{

if(a[i]=='Z')

{a[i]='a';}

else if(a[i]>='A'&&a[i]<='Y')

{a[i]=a[i]+33;}

else if(a[i]=='a'||a[i]=='b'||a[i]=='c')

{a[i]='2';}

else if(a[i]=='d'||a[i]=='e'||a[i]=='f')

{a[i]='3';}

else if(a[i]=='g'||a[i]=='h'||a[i]=='i')

{a[i]='4';}

else if(a[i]=='j'||a[i]=='k'||a[i]=='l')

{a[i]='5';}

else if(a[i]=='m'||a[i]=='n'||a[i]=='o')

{a[i]='6';}

else if(a[i]=='p'||a[i]=='q'||a[i]=='r'||a[i]=='s')

{a[i]='7';}

else if(a[i]=='t'||a[i]=='u'||a[i]=='v')

{a[i]='8';}

else if(a[i]=='w'||a[i]=='x'||a[i]=='y'||a[i]=='z')

{a[i]='9';}

else

a[i]=a[i];

}

}

puts(a);

    return 0;

}