回文数(一) （C语言代码）

#include <stdio.h>
int main()
{
     int i,j=0,k,t1=0,t2=0,t3=0,s=0,s1=0,s2=0,flag=2,step=0,L;
     int a[1000],b[1000];

     scanf("%d",&L);
     for(i=0;i<L;i++)
          scanf("%d",&a[i]);

      for(i=0;i<L;i++)
      {
           step=0;t1=a[i];t2=a[i];t3=0;;s=0;s1=0;s2=0;flag=2;
           while(flag!=1)
           {
                    while(t1!=0)
                    {
                             t3=t3*10+t1%10;
                             t1/=10;
                     };
                     s=t2+t3;
                     s1=s;
                     while(s1!=0)
                     {
                               s2=s2*10+s1%10;
                               s1/=10;
                      };
                      if(s2==s)flag=1;
                      else{t1=s;t2=s;t3=0;s1=0;s2=0;};
                      step++;
              };
              b[j++]=step;
        }

        for(k=0;k<j;k++)
        {
             if(b[k]<=8)
             {
                if(k<j-1)printf("%d\n",b[k]);
                else printf("%d",b[k]);
             }
             else
             {
                    if(k<j-1)printf("0\n");
                    else printf("0");
              }
         }

         return 0;
}

解题思路:





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参考代码: