原题链接：[编程入门]结构体之时间设计
解题思路:
用一个长度为12的数组，记录每个月的天数，除了2月先不记录；
输入日期，判断闰年2月赋值29，平年28；
计算是第几天，输出；
参考代码:
#include <stdio.h>
#include <iostream>
using namespace std;
class riqi {
private:
int year;
int month;
int day;
public:
riqi( int y, int m, int d )
{
year = y;
month = m;
day = d;
}
void count();
};
void riqi::count()
{
int n = 0;
int a[12];
a[0] = 31;
a[1] = 0;
a[2] = 31;
a[3] = 30;
a[4] = 31;
a[5] = 30;
a[6] = 31;
a[7] = 31;
a[8] = 30;
a[9] = 31;
a[10] = 30;
a[11] = 31;
if ( year % 100 == 0 ) //判断年数为2000这样的年份
{
if ( year % 400 == 0 )
a[1] = 29;
else
a[1] = 28;
}
if ( year % 4 == 0 && year % 100 != 0 ) //能被4整除但不能被100整除
a[1] = 29;
if ( year % 4 != 0 )
a[1] = 28;
for ( int i = 0; i < month - 1; i++ ) //数组下标从0开始，所以month-1
n = n + a[i];
n += day;
cout << n;
}
int main()
{
int Y, M, D;
cin >> Y;
cin >> M;
cin >> D;
riqi A( Y, M, D );
A.count();
return(0);
}几个月前写的，翻出来弄题解，讲的思路没有写的时候清晰～
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#include<iostream> int main(int argc, char *argv[]){ int year,month,day; int sum = 0; std::cin>>year>>month>>day; if((year%4==0 && year%100!=0) || (year%400==0)){ sum+=1; } for(int i = 1; i<month; i++){ if(i==1 || i==3 || i==5 || i==7 || i==8 || i == 10 || i==12){ sum+=31; } else if(i == 2){ sum+=28; } else{ sum+=30; } } sum+=day; std::cout<<sum; }#include<stdio.h> int leap_year(int y); struct year { int tear; int yue; int ru; }temp; int main() { int t=0,a=0; int b[12] = {31,29,31,30,31,30,31,31,30,31,30,31}; int c[12] = {31,28,31,30,31,30,31,31,30,31,30,31}; scanf_s("%d%d%d",&temp.tear,&temp.yue,&temp.ru); t = leap_year(temp.tear); if (t == 1) for (int i = 0; i < temp.yue-1; i++) a += c[i]; if (t == 0) for (int i = 0; i < temp.yue - 1; i++) a += b[i]; printf("%d",temp.ru+a); return 0; } int leap_year(int y) { if ((y % 400 == 0 || (y % 100 != 0 && y % 4 == 0))) return 0; else return 1; } 欢迎点评#include <stdio.h> struct Time { int year; int month; int day; }; int main(void) { struct Time time; int i, year, month, day; int sum = 0; int y[12] = {31,28,31,30,31,30,31,31,30,31,30,31}; scanf("%d%d%d", &time.year, &time.month, &time.day); sum = time.day; for (i = 0; i < time.month - 1; i++) { sum += y[i]; } if ((time.year % 400 == 0) || (time.year % 4 == 0 && time.year % 100 != 0) && (time.month > 2)) printf("%d", sum + 1); else printf("%d", sum); return 0; }有大佬帮忙看一下哪里错了吗？错误50% #include <iostream> using namespace std; struct Data { int year; int month; int day; }; int main() { Data time; int a[12]={31,28,31,30,31,30.31,31,30,31,30,31},day=0; cin>>time.year>>time.month>>time.day; if((time.year%4==0&&time.year%100!=0)||time.year%400==0) a[1]=29; for(int i=0;i<time.month-1;i++) day=day+a[i]; day=day+time.day; cout<<day<<endl; return 0; }#include <stdio.h> int main() { struct dd { int year; int month; int day; }st1; int sum = 0; int a[][13]={ {0,31,28,31,30,31,30,31,31,30,31,30,31}, {0,31,29,31,30,31,30,31,31,30,31,30,31} }; scanf ("%d%d%d",&st1.year,&st1.month,&st1.day); int leap = 0; leap = ( st1.year % 4 == 0 && st1.year %100 != 0 || st1.year % 400 == 0 ); while ( st1.month > 0){ st1.month--; sum += a[leap][st1.month]; } sum += st1.day; printf("%d",sum); }#include<stdio.h> struct date{ int year; int month; int day; }aa; void main(){ int a[12]={31,28,31,30,31,30,31,31,30,31,30,31},t=0; scanf("%d%d%d",&aa.year,&aa.month,&aa.day); if(aa.year%100==0&&aa.year%400==0||aa.year%100!=0&&aa.year%4==0){ a[1]=29; } for(int i=0;i<aa.month-1;i++){ t=t+a[i]; } printf("%d\n",t+aa.day); }