回文数(一) （C语言代码）

解题思路:





注意事项:





参考代码:

#include <stdio.h>

#include <math.h>

int main(void)

{

int i, j, l, k, m, x, y, z, h, gaowei, diwei, sum, count, count1;

int num[10];

scanf("%d", &l);

for (i = 1;i <= l;i++)

{

count = 0;

scanf("%d", &m);

while (count <= 8)

{

count1 = 0;

sum = 0;

x = m;

j = 0;

while (x != 0)

{

num[j] = x % 10;

x = x / 10;

j++;

}

z = 0;

while (j != 0)

{

sum = sum + pow(10, z)*num[j - 1];

z++;

j--;

}

m = m + sum;

x = m;

count++;

y = 0;

while (x != 0)

{

x = x / 10;

y++;

}

x = m;

for (k = 1, h = y - k;k <= y / 2;k++)

{

gaowei = x / pow(10, h);

diwei = x % 10;

x = x - gaowei*pow(10, h);

x = x / 10;

h = h - 2;

if (gaowei == diwei)

count1++;

else

{

count1 = 0;

break;

}

}

if (count1 == y / 2)

{

printf("%d\n", count);

break;

}

}

if (count > 8)

printf("0\n");

}

}