C语言程序设计教程（第三版）课后习题11.1 （C++代码）

解题思路:





注意事项:





参考代码:

#include <iostream>

using namespace std;

int main()

{

int n,y,r,i;

cin>>n>>y>>r;

switch(y)

{

case 1:i=r;break;

case 2:i=31+r;break;

case 3:i=31+28+r;break;

case 4:i=31+28+31+r;break;

case 5:i=31+28+31+30+r;break;

case 6:i=31+28+31+30+31+r;break;

case 7:i=31+28+31+30+31+30+r;break;

    case 8:i=31+28+31+30+31+30+31+r;break;

case 9:i=31+28+31+30+31+30+31+31+r;break;

case 10:i=31+28+31+30+31+30+31+31+30+r;break;

case 11:i=31+28+31+30+31+30+31+31+30+31+r;break;

case 12:i=31+28+31+30+31+30+31+31+30+31+30+r;break;

}

if((n%4==0&&n%100!=0)||(n%400==0))

if(y>=3) i=i+1;

cout<<i<<endl;

return 0;

}