矩形面积交 （Java代码）

解题思路:





注意事项：





参考代码:

package T14;

import java.text.DecimalFormat;

import java.util.Scanner;

public class T71 {

public static void main(String[] args) {

Scanner sc=new Scanner (System.in);

double []x=new double[4];

double []y=new double[4];

for(int i=0;i<4;i++){

x[i]=sc.nextDouble();

y[i]=sc.nextDouble();

}

danan(x,y);

}

public static double max(double a,double b){

return ((a>b)?a:b);

}

public static double min(double a,double b){

return (a<b)?a:b;

}

public static void danan(double [] x,double []y){

double x1=max(min(x[1],x[0]),min(x[3],x[2]));

double y1=max(min(y[1],y[0]),min(y[3],y[2]));

double x2=min(max(x[1],x[0]),max(x[3],x[2]));

double y2=min(max(y[1],y[0]),max(y[3],y[2]));

double x3=x2-x1;double y3=y2-y1;

if(x3>0&&y3>0){

double s=(x2-x1)*(y2-y1);

DecimalFormat de =new DecimalFormat("##0.00");

System.out.println(de.format(s));}

else System.out.println("0.00");

}

}