矩形面积交 （Java代码）

解题思路:





注意事项:
本题解在eclipse上运行无误，但是在这里运行显示运行错误，（仅供参考）




参考代码:

import java.util.Scanner;

import java.text.DecimalFormat;

public class Main {

        public static void Rect(int[] arrayA,int[] arrayB){

                DecimalFormat df = new DecimalFormat("0.00");

                if(arrayB[0]>arrayA[2]||arrayB[1]>arrayA[3])

                        System.out.println("两矩形没有相交！");

                else

                        System.out.print(df.format((arrayA[3]-arrayB[1])*(arrayA[2]-arrayB[0])));

       }

        public static void main(String[] arg){

                Scanner sc = new Scanner(System.in);

                int[] arrayA = new int[4];

                int[] arrayB = new int[4];

                for(int i=0;i<4;i++){

                        arrayA[i] = sc.nextInt();

                }

                for(int i=0;i<4;i++){

                        arrayB[i] = sc.nextInt();

                }

                Rect(arrayA, arrayB);

        }

}