莉露编写题解 2837: 年龄与疾病

解题思路:
if语句多个
注意事项:
只有%%才可以在20.00后输出%，否则只输出20.00

参考代码:

#include<stdio.h>

#define MAX 100

int main(){

    int n;

    scanf("%d",&n);

    int a[MAX] = {0};

    int* p = a;

    double b=0,c=0,d=0,e=0;

    for(int i=0;i<n;i++)

        scanf("%d",p + i);

    for(int i=0; i<n; i++){

        int current_age = *(p+i);

        if(current_age <= 18){   

            b += 1;

            continue;

        }

        if(current_age <= 35){   

            c += 1;

            continue;

        }

        if(current_age <= 60){   

            d += 1;

            continue;

        }

        e += 1;

    }

    printf("%.2lf%%\n",b*100/n);

    printf("%.2lf%%\n",c*100/n);

    printf("%.2lf%%\n",d*100/n);

    printf("%.2lf%%\n",e*100/n);

    return 0;

}