2819:数字反转

解题思路:

注意事项:

参考代码:

#include<stdio.h>

int main()

{

int num,remained,reserved=0;

scanf("%d",&num);

int sign=(num>0)?1:-1;

num=fabs(num);

while(num!=0)

{

    remained=num%10;

    reserved=reserved*10+remained;

    num/=10;

}

num=reserved*sign;

printf("%d\n",num);

return 0;

}