简单易懂的写法

解题思路:

注意事项:

参考代码:

#include<bits/stdc++.h>

using namespace std;

struct year_month_day{

        int year;

        int month;

        int day;

    };

bool Is_Leap(int year){

    if((year%4==0&&year%100!=0)||(year%400==0))

        return true;

    else

        return false;

}

void my_judge(int year,int month,int day){

    int cnt=0;

    int each_month[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};

    Is_Leap(year)?each_month[2]=29:each_month[2]=28;

    for(int i=1;i<month;i++){

        cnt=cnt+each_month[i];

    }

        cnt=cnt+day;

    cout<<cnt;

}

int main()

{

    year_month_day date;

    cin>>date.year>>date.month>>date.day;

    my_judge(date.year,date.month,date.day);

    return 0;

}