题目 1010: [编程入门]利润计算

解题思路:读题看清题目要求在用if语句做判断

注意事项:计算条件一定要看清

参考代码:

#include"stdio.h"

void main()

{   

int l;

scanf("%d",&l);

if (l <= 100000)

{

float sum;

sum = l * 0.1;

printf("%0.f\n",sum);

}

else if (100000<l && l<=200000)

{

float sum;

sum = (100000 * 0.1) + ((l-100000) * 0.075);

printf("%0.f\n",sum);

}

else if (200000<l && l<=400000)

{

float sum;

sum = (100000*0.1) + (100000*0.075) + (l-200000) * 0.05;

printf("%0.f\n",sum);

}

else if (400000<l && l<=600000)

{

float sum;

sum = (100000*0.1) + (100000*0.075) + (200000*0.05) + (l-400000) * 0.03;

printf("%0.f\n",sum);

}

else if (600000<l && l<=1000000)

{

float sum;

sum = (100000*0.1) + (100000*0.075) + (200000*0.05) + (200000*0.03) + (l-600000) * 0.015;

printf("%0.f\n",sum);

}

else if (l>1000000)

{

float sum;

sum = (100000*0.1) + (100000*0.075) + (200000*0.05) + (200000*0.03) + (400000*0.015) + (l-1000000) * 0.01;

printf("%0.f\n",sum);

}

return 0;

}