津津的储蓄计划（python版）

解题思路:

注意事项:

参考代码:def progress(x,y):
   if x<y:
       return -1
   else:
       less=x-y
       return less

def cunchu(x,y):
   if x-y>=100:
       m=(x-y)//100
       less=x-m*100
       chucun=m*100
       return less,chucun
   else:
       return x,0
y=[0]*12
m=300
x=0
less=0
all_result=0
for i in range(12):
   y[i]=eval(input())

for i in range(12):
   current=m+x
   x,less=cunchu(current,y[i])
   progress_result=progress(x,y[i])
   if progress_result == -1:
       print(-(i + 1))
       break
   else:
       x=progress_result
       all_result+=less
else:
   total=x+all_result*1.2
   print(int(total))