结构体之成绩统计2（C语言）---谢谢查看

解题思路:

注意事项:

参考代码:

#include<stdio.h>

#include<stdlib.h>

struct student{

char xuehao[5];

char name[20];

int score[3];

};

void input(struct student *p,int n){

for(int i=0;i<n;i++){

scanf("%s%s%d%d%d",p->xuehao,p->name,&p->score[0],&p->score[1],&p->score[2]);

p++;

}

p=p-n;

}

void print(struct student *p,int n){

for(int i=0;i<n;i++){

printf("%s,%s,%d,%d,%d\n",p->xuehao,p->name,p->score[0],p->score[1],p->score[2]);

p++;

}

p=p-n;

} 

struct student * max(struct student *p,int n){

int max=0,m=0;

int *sum = (int *)malloc(sizeof(int)*n);

struct student *q=p;

for(int i=0;i<n;i++){

*sum=p->score[0]+p->score[1]+p->score[2];

p++;

sum++;

}

p-=n;

sum-=n;

for(int i=0;i<n;i++){

if(max<*(sum+i)){

max=*(sum+i);

q=p;

}

p++;

}

p=p-n;

return q;

}

int main(){

int N,i;

int score1=0,score2=0,score3=0;

scanf("%d",&N);

void input(struct student *p,int n);

void print(struct student *p,int n);

struct student * max(struct student *p,int n); 

struct student *p = (struct student *)malloc(sizeof(struct student)*N);

struct student *q=p;

input(p,N);

for(int i=0;i<N;i++){

score1+=p->score[0];

score2+=p->score[1];

score3+=p->score[2];

p++;

}

p=p-N;

printf("%d %d %d\n",score1/N,score2/N,score3/N);

q=max(p,N);

printf("%s %s %d %d %d\n",q->xuehao,q->name,q->score[0],q->score[1],q->score[2]);

return 0;

}