解题思路:
注意事项:
参考代码:
def to_octal(num):
if num == 0:
return '0'
octal_digits = []
while num > 0:
remainder = num % 8
octal_digits.append(str(remainder))
num = num // 8
octal_digits.reverse()
octal_string = ''.join(octal_digits)
return octal_string
num = int(input())
oct_num = to_octal(num)
print(oct_num) # 输出:52
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