2810: 鸡尾酒疗法

解题思路:

注意事项:

参考代码:

#include <iostream>

using namespace std;

int main()

{

    double n,x,y,j,k;

    cin>>n>>x>>y;

    k=y/x;

    for(int i=1;i<=n-1;i++)

    {

        cin>>x>>y;

        j=y/x;

        if(j-k>0.05)

        {

            cout<<"better"<<endl;

        }

        else if(k-j>0.05)

        {

            cout<<"worse"<<endl;

        }

        else

        {

            cout<<"same"<<endl;

        }

    }

    return 0;

}