解题思路:按照题目中要求的数据分步计算,多次用到else if的判断
注意事项:等号的顺序
参考代码:
#include<stdio.h>
int main()
{
int i;
int bouns,bouns1,bouns2,bouns3,bouns4,bouns5;
scanf("%d",&i);
bouns1=100000*0.1;
bouns2=bouns1+100000*0.075;
bouns3=bouns2+200000*0.05;
bouns4=bouns3+200000*0.03;
bouns5=bouns4+400000*0.015;
if(i<=100000){
bouns=i*0.1;
printf("%d",bouns);
}
else if (i<=200000){
bouns=bouns1+(i-100000)*0.075;
printf("%d",bouns);
}
else if (i<=400000){
bouns=bouns2+(i-200000)*0.05;
printf("%d",bouns);
}
else if (i<=600000){
bouns=bouns3+(i-400000)*0.03;
printf("%d",bouns);
}
else if (i<=1000000){
bouns=bouns4+(i-600000)*0.015;
printf("%d",bouns);
}
else if (i>1000000){
bouns=bouns5+(i-1000000)*0.01;
printf("%d",bouns);
}
}
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