28行代码解决

解题思路:

注意事项:

参考代码:

#include <iostream>

using namespace std;

int main() {

    int n;

    cin >> n;

    int a[10000];

    for(int i = 0; i < n; i++){

    string s1,s2;

    cin >> s1 >> s2;

    if(s1 == "Rock" && s2 ==  "Scissors"||s1 == "Scissors" && s2 ==  "Paper"||s1 == "Paper" && s2 ==  "Rock")

    a[i] = 1;

    else if(s2 == "Rock" && s1 ==  "Scissors"||s2 == "Scissors" && s1 ==  "Paper"||s2 == "Paper" && s1 ==  "Rock")

a[i] = 2;

else 

a[i] = 3;

}

    for(int i = 0; i < n; i++){

    if(a[i] == 1)

    cout << "Player1" << endl;

    if(a[i] == 2)

    cout << "Player2" << endl;

    if(a[i] == 3)

    cout << "Tie" << endl;

}

    return 0;

}