利用二位数组求解

解题思路:

注意事项:

参考代码:

import java.util.Scanner;

public class Main{

/**

* @param args

*/

public static void main(String[] args) {

// TODO Auto-generated method s

Scanner sc=new Scanner(System.in);

int n=sc.nextInt();

int a[][]=new int[n][n];

int i,j;

//int count1,count2=0;

for(i=0;i<n;i++)

for(j=0;j<n;j++)

a[i][j]=sc.nextInt();

int count1=0,count2=0;

int count3=0;

int i1=0;

for(i=0;i<n;i++)

{

count1=0;

for(j=0;j<n;j++)

{

if(a[i][j]==1)

count1++;

}

if(count1%2==1)

{

count3++;

i1=i;

}

}

int count4=0;

int j1=0;

for(j=0;j<n;j++)

{

count2=0;

for(i=0;i<n;i++)

{

if(a[i][j]==1)

count2++;

}

if(count2%2==1)

{

count4++;

j1=j;

}

}

if(count3==0&&count4==0)

System.out.println("OK");

else if(count3==1&&count4==1)

System.out.println((i1+1)+" "+(j1+1));

else

System.out.println("Corrupt");

}

}