解题思路: 两个最小堆
参考代码:
import java.util.*; import java.io.*; import java.math.*; public class Main { static void Solve() throws IOException { int n = sc.nextInt(); int[] a = new int[n + 1]; Queue<Integer> q = new PriorityQueue<>((o1, o2) -> o2 - o1); for (int i = 1; i <= n; i++) { a[i] = sc.nextInt(); q.offer(a[i]); } Queue<Integer> p = new PriorityQueue<>((o1, o2) -> o2 - o1); long cnt = 0; while (!q.isEmpty()) { while (!p.isEmpty() && !q.isEmpty() && p.peek() >= q.peek()) { p.poll(); int o = q.poll(); //out.println("免费的是 :" + o); } if (!q.isEmpty()) { int v = q.poll(); cnt += v; //out.println("买入大的 :" + v); } if (!q.isEmpty()) { while (!p.isEmpty() && !q.isEmpty() && p.peek() >= q.peek()) { p.poll(); int o = q.poll(); //out.println("免费的是 :" + o); } if (!q.isEmpty()){ int t = q.poll(); cnt += t; //out.println("买入小的 :" + t); p.add(t / 2); //out.println("买入小的p添加一半后是 :" + (t / 2)); } } } out.println(cnt); } /* */ public static void main(String[] args) throws IOException { int t = 1; // int t = sc.nextInt(); while (t-- > 0) Solve(); out.flush(); out.close(); br.close(); } static PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out)); static Input sc = new Input(System.in); static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); static class Input { public BufferedReader reader; public StringTokenizer tokenizer; public Input(InputStream stream) { reader = new BufferedReader(new InputStreamReader(stream), 32768); tokenizer = null; } public String next() { while (tokenizer == null || !tokenizer.hasMoreTokens()) { try { tokenizer = new StringTokenizer(reader.readLine()); } catch (IOException e) { throw new RuntimeException(e); } } return tokenizer.nextToken(); } public int nextInt() { return Integer.parseInt(next()); } public long nextLong() { return Long.parseLong(next()); } public Double nextDouble() { return Double.parseDouble(next()); } public BigInteger nextBigInteger() { return new BigInteger(next()); } } }
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