c语言代码解决问题

解题思路:

注意事项:

参考代码:

#include<stdio.h>

#include<string.h>

int main()

{

char str1[201], str2[201];

scanf("%s%s", str1, str2);

int i, j, a[200], b[200]={0}, result[200] = {0}, len1 = strlen(str1), len2 = strlen(str2);

for (i = 0; i < len1; i++)

{

j = len1 - i - 1;

a[i] = (int)(str1[j] - '0');

}

for (i = 0; i < len2; i++) 

{

j = len2 - i - 1;

b[i] = (int)(str2[j] - '0');

}

for (i = 0; i < len1; i++)

{

if (a[i] - b[i] < 0)

{

result[i] = 10 + a[i] - b[i];

a[i + 1]--;

}

else

result[i] = a[i] - b[i];

}

int k = len1 - 1;

while (result[k] == 0)

{

k--;

}

if (k == -1)

{

printf("0");

}

else

{

for (i = k; i >= 0; i--)

printf("%d", result[i]);

}

return 0;

}