蓝桥杯历届试题-翻硬币

解题思路:

注意事项:

参考代码:

n=list(input())
m=list(input())
count=0
for i in range(len(m)):
    if n[i]!=m[i]:
        if n[i]=="o":
            n[i]="*"
            if n[i+1]=='o':
                n[i+1]='*'
            else:
                n[i+1]='o'
        else:
            n[i]='o'
            if n[i+1]=='o':
                n[i+1]='*'
            else:
                n[i+1]='o'
        count+=1
print(count)