括弧匹配检验

解题思路:

注意事项:

参考代码:

def is_matching(expression):
   stack = []
   mapping = {')': '(', ']': '['}

   for char in expression:
       if char in mapping.values():
           stack.append(char)
       elif char in mapping.keys():
           if not stack or mapping[char] != stack.pop():
               return 'Wrong'

   return 'OK' if len(stack) == 0 else 'Wrong'


expression = input()
result = is_matching(expression)
print(result)