题解列表

摘要：解题思路:注意事项:参考代码:#include <iostream>#include <iomanip>using namespace std;int main(){ int n,sum1=0,sum……

摘要：解题思路:注意事项:参考代码:#include<stdio.h>int main (){ int sum=0,X,i,Y;scanf("%d %d",&X,&Y); for(i=X;i>=X&&i<=……

摘要：解题思路:注意事项:参考代码:#include <iostream>using namespace std;int main(){ int n,m; for(int i=1;i<=23;i++) { ……

摘要：解题思路:注意事项:参考代码:#include <iostream>using namespace std;int main(){ int n,sum; cin>>n; sum=(2+2+3*(n-1……

摘要：解题思路:注意事项:参考代码:#include <iostream>#include <iomanip>#include <cmath>using namespace std;int main(){ ……

摘要：解题思路:注意事项:参考代码:#include <iostream>#include <iomanip>using namespace std;int main(){ double x,y; cin>……

摘要：解题思路:注意事项:参考代码:#include <iostream>#include <iomanip>using namespace std;int main(){ double x,y; cin>……

摘要：解题思路:注意事项:参考代码:#include <iostream>#include <iomanip>using namespace std;int main(){ double m,n; cin>……

摘要：解题思路:注意事项:参考代码:n = int(input())x = str(input())m = int(input())print(x[m-1:])……

摘要：解题思路:注意事项:参考代码:#include <stdio.h>int main (){ int N,sum=0,i;scanf("%d",&N); for (i=1;i<=N;i++) { if……