题解列表

摘要：解题思路:注意事项:参考代码:#include <stdio.h>int main(){ int n; scanf("%d",&n); if(n%2>0) { printf("odd",n); } ……

摘要：解题思路:注意事项:参考代码:#include<iostream>using namespace std;#include<stack>stack<char> s;int main(){    int……

摘要：解题思路:注意事项:参考代码:#include<stdio.h>int main(){ int n,t=0; scanf("%d", &n); for (t = 2; t < n; t++) { i……

摘要：解题思路:注意事项:参考代码:#include <stdio.h>int main(){ int a,b,c,z; scanf("%d %d %d",&a,&b,&c); z=a+(c-1)*(b……

摘要： char a = scanner.next().charAt(0); System.out.println((int)a); cha……

摘要：解题思路:注意事项:参考代码:#include<stdio.h>int main(){ long long int n,sn=0; scanf("%lld", &n); long long int a……

摘要： import java.util.Scanner; public class Main { public static void main(String[] ……

摘要：```cpp #include using namespace std; unsigned long long int jiecheng(int n) { if(n==0) ……

摘要：```cpp #include #include using namespace std; int main() { int n; while(cin>>n&&n) ……

摘要：解题思路:注意事项:参考代码:#include<stdio.h>#define LEAP_YEAP(y) ((y%4==0&&y%100!=0)||(y%400==0))?L:Nint main(){……