蓝桥杯基础练习VIP-报时助手-题解（C++代码）利用开关语句，一个函数解决。
摘要：解题思路:条件明确，数字和字母表示一一对应。所以想到运用开关语句。注意事项:1.函数封装。为了减少操作，利用递归思想对20到60间的非特殊数字采用递归。参考代码:#include<iostream>#……
蓝桥杯基础练习VIP-报时助手-题解（C语言代码）
##解题思路:利用数组a存放时钟里所有可能出现的英文，在对应的输入之后，进行判断然后输出。##注意事项:指针数组相当于二维数组存放数据。##参考代码:```#includeintmain(){inth,m;scanf("%d%d",&h,&m);char*a[]={"zero",
蓝桥杯基础练习VIP-报时助手-题解（C++代码）
摘要：```
#include
using namespace std;
const char* s[60]={"zero","one","two","three","four","five",……
蓝桥杯基础练习VIP-报时助手-题解(Java代码)Java的伙伴看这里
```javaimportjava.util.Scanner;publicclassMain{//报时助手publicstaticvoidmain(String[]args){String[]time=newString[]{"zero","one",
蓝桥杯基础练习VIP-报时助手-题解（C语言代码）
#include#includeintmain(){inth,m,a,b;chars[24][10]={"zero","one","two","three","four","five","six","seven","eight","nine",
蓝桥杯基础练习VIP-报时助手-题解(C语言代码)
摘要：有点复杂
char number[][10]={"zero","one","two","three","four","five","six","seven","eight","nine","ten"……
蓝桥杯基础练习VIP-报时助手-题解(C语言代码)
摘要：
#include
void cl(int h,int m)//处理并输出函数
{
char a[50][50]={{"zero"}, {"one"},{"two"}, {"three"},……
蓝桥杯基础练习VIP-报时助手-题解(C语言描述。枚举的运用)
```c#includeenumtimes{zero,one,two,three,four,five,six,seven,eight,nine,ten,eleven,twelve,thirteen,fourteen,fifteen,sixteen,
蓝桥杯基础练习VIP-报时助手-题解(Java代码)
```javaimportjava.util.*;publicclassMain{publicstaticvoidmain(String[]args){Scannersc=newScanner(System.in);inth=sc.nextInt();intm=sc.nextInt();Stringa
蓝桥杯基础练习VIP-报时助手-题解(Java代码)
```javaimportjava.util.Scanner;publicclassMain{publicstaticvoidmain(String[]args){Scannersc=newScanner(System.in);inth=sc.nextInt();intm=sc.nextInt();S