A+B for Input-Output Practice (VI)-题解(C++代码)
```cpp#includeusingnamespacestd;intmain(){intn_int=0;inta_int=0;intc_int=0;while(cin>>n_int){c_int=0;while(n_int>0){cin>>a_int;c_int+=a_int;n_int--;}co
A+B for Input-Output Practice (VI)-题解(C++代码)
```cpp#includeusingnamespacestd;intmain(){inta;intn;intsum;inti;while((cin>>n)&&n!=NULL){sum=0;for(i=1;i>a;sum+=a;}cout
A+B for Input-Output Practice (VI)-题解(C语言代码)
摘要：#include
int main()
{
int n;
int i,a,j,s=0;
while(~scanf("%d",&n))
{
for(i=1;i……
A+B for Input-Output Practice (VI)-题解(C语言代码)
题目：输入：41234512345输出：1015#includeintmain(){intn,i,j=0,m;intsum=0,b[10];//数组b要定义数量，最好是10while(scanf("%d",&n)!=EOF&&n!=0)//这个范围要固定，这个为最佳范围{for(i=0;i
A+B for Input-Output Practice (VI)-题解(Java代码)
```importjava.util.Scanner;publicclassMain{publicstaticvoidmain(String[]args){Scannersc=newScanner(System.in);while(sc.hasNext()){intg=sc.nextInt();int
A+B for Input-Output Practice (VI)-题解(C++代码)
摘要：```cpp
#include
using namespace std;
int main()
{
int a;
int N;
while(cin>>N&&N!=……
A+B for Input-Output Practice (VI)-题解（C语言代码）
摘要： #include
int main()
{
int a,i,j;
int sum;
while(scanf("%d",……
A+B for Input-Output Practice (VI)-题解（C语言代码）
摘要：```c
#include
int main()
{
int a[100];
while (scanf("%d", &a[0]) != EOF)
{
……
A+B for Input-Output Practice (VI)-题解（Java代码）
解题思路:注意事项:参考代码:importjava.util.Scanner;/**************题目1090:A+BforInput-OutputPractice(VI)**********************/publicclassMain{publicstaticvoidmain(
A+B for Input-Output Practice (VI)-题解（C语言代码）
摘要：解题思路:注意事项:参考代码:#include<stdio.h>int main(){ int i, x, m, sum = 0, n; while(~scanf("%d", &n)){ ……