利用列表内置函数解决

解题思路:
利用list函数count
注意事项:

参考代码:times = int(input())
s = []
for i in range(times):
   s += [j for j in map(int, input().split())]
minNum = min(s)
length = len(s)
compare = [minNum + i for i in range(length)]
idDuan, idChong = 0, 0
for i in range(length):
   s.append(compare[i])
   if s.count(compare[i]) == 3:
       idChong = compare[i]
   if s.count(compare[i]) == 1:
       idDuan = compare[i]
print(idDuan, idChong)