循环嵌套实现DNA(C++)

解题思路:

注意事项:

参考代码:

#include

using namespace std;

int main()

{

         int N, a, b, n = 1;

         cin >> N;

         while(n <= N)

         {

                 cin >> a >> b;

                 int k = 1;

                 while(k <= b)

                 {

                         for(int i = 1; i <= (k == b?a:(a-1)); i++)    //还没输出最后一组“图形”前，每组输出只输出前a-1行，最后一组输出加上本组第a行。

                         {

                                 for(int j = 1; j <= a; j++)

                                 {

                                         if(j == i || j == (1 + a - i))

                                         {

                                                  cout << 'X';

                                         }

                                         else

                                         {

                                                  cout << ' ';

                                         }

                                  }

                                 cout << endl;

                          }

                         k++;

                    }

                    cout << endl;

                    n++;

             }

            return 0;

}