1147-角谷猜想(代码简洁,思路清晰)

解题思路:

注意事项:

0是自然数、偶数、整数，不是正整数，所以不考虑0 

参考代码:

#include<iostream>

using namespace std;

int main()

{

    int n,t;

    cin >>n;

    while(n!=1)

    {

        if(n%2==0)

        {

              t=n/2;

              printf("%d/2=%d\n",n,t);

              n=t;

        }

        else if(n%2!=0)

        {

              t=n*3+1;

              printf("%d*3+1=%d\n",n,t);

              n=t;

        }

    }

}