解题思路:
找规律。
创建一个二维数组,初始化为空格。然后将*进行填充。
先将图形的右上角部份填充完成,然后左右对称,然后上下对称。
将结果打印输出即可。
注意事项:
参考代码:
width = int(input().strip()) A = [[' ' for j in range(width+1)] for i in range(width+1)] ctr = width // 2 A[ctr][ctr] = '*' A[ctr][ctr+1] = '*' A[ctr+1][ctr] = '*' A[ctr+1][ctr+1] = '*' n = (width-2)//4 for i in range(1,n+1): temp = ctr + 1 + 2*i for j in range(2*i+1): A[ctr-j][temp] = '*' temp = ctr - 2*i for j in range(2*i): A[temp][ctr+1+j] = '*' for j in range(1,width//2+1): for i in range(1,width//2+1): A[i][j] = A[i][width+1-j] for i in range(width//2+1,width+1): A[i] = A[width+1-i] for i in range(1,width+1): for j in range(1,width+1): print(A[i][j],end='') print()
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