原题链接:蓝桥杯基础练习VIP-报时助手
解题思路:将特殊的时间都存放在数组中,方便后面直接输出
注意事项:
参考代码:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
String[] strs = { "zero", "one", "two", "three", "four", "five", "six",
"seven", "eight", "nine", "ten", "eleven", "twelve",
"thirteen", "fourteen", "fifteen", "sixteen", "seventeen",
"eighteen", "nineteen", "twenty", };
Scanner scanner = new Scanner(System.in);
int h = Integer.parseInt(scanner.next());
String sh = "";
int m = Integer.parseInt(scanner.next());
String sm = "";
if (h <= 20) {
sh = strs[h];
} else if (h < 30) {
sh = "twenty " + strs[h - 20];
} else if (h < 40) {
if (h == 30)
sh = "thirty";
sh = "thirty " + strs[h - 30];
} else if (h < 50) {
if (h == 40)
sh = "forty";
sh = "forty " + strs[h - 40];
} else if (h < 60) {
if (h == 50)
sh = "fifty";
sh = "fifty " + strs[h - 50];
}
if (m == 0) {
sm = "o'clock";
} else if (m <= 20) {
sm = strs[m];
} else if (m < 30) {
sm = "twenty " + strs[m - 20];
} else if (m < 40) {
if (m == 30)
sm = "thirty";
sm = "thirty " + strs[m - 30];
} else if (m < 50) {
if (m == 40)
sm = "forty";
sm = "forty " + strs[m - 40];
} else if (m < 60) {
if (m == 50)
sm = "fifty";
sm = "fifty " + strs[m - 50];
}
System.out.println(sh + " " + sm);
}
}0.0分
1 人评分
C语言网提供由在职研发工程师或ACM蓝桥杯竞赛优秀选手录制的视频教程,并配有习题和答疑,点击了解:
一点编程也不会写的:零基础C语言学练课程
解决困扰你多年的C语言疑难杂症特性的C语言进阶课程
从零到写出一个爬虫的Python编程课程
只会语法写不出代码?手把手带你写100个编程真题的编程百练课程
信息学奥赛或C++选手的 必学C++课程
蓝桥杯ACM、信息学奥赛的必学课程:算法竞赛课入门课程
手把手讲解近五年真题的蓝桥杯辅导课程
发表评论 取消回复