原题链接:蓝桥杯基础练习VIP-报时助手
解题思路:将特殊的时间都存放在数组中,方便后面直接输出
注意事项:
参考代码:
import java.util.Scanner; public class Main { public static void main(String[] args) { String[] strs = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen", "twenty", }; Scanner scanner = new Scanner(System.in); int h = Integer.parseInt(scanner.next()); String sh = ""; int m = Integer.parseInt(scanner.next()); String sm = ""; if (h <= 20) { sh = strs[h]; } else if (h < 30) { sh = "twenty " + strs[h - 20]; } else if (h < 40) { if (h == 30) sh = "thirty"; sh = "thirty " + strs[h - 30]; } else if (h < 50) { if (h == 40) sh = "forty"; sh = "forty " + strs[h - 40]; } else if (h < 60) { if (h == 50) sh = "fifty"; sh = "fifty " + strs[h - 50]; } if (m == 0) { sm = "o'clock"; } else if (m <= 20) { sm = strs[m]; } else if (m < 30) { sm = "twenty " + strs[m - 20]; } else if (m < 40) { if (m == 30) sm = "thirty"; sm = "thirty " + strs[m - 30]; } else if (m < 50) { if (m == 40) sm = "forty"; sm = "forty " + strs[m - 40]; } else if (m < 60) { if (m == 50) sm = "fifty"; sm = "fifty " + strs[m - 50]; } System.out.println(sh + " " + sm); } }
0.0分
1 人评分
C语言网提供由在职研发工程师或ACM蓝桥杯竞赛优秀选手录制的视频教程,并配有习题和答疑,点击了解:
一点编程也不会写的:零基础C语言学练课程
解决困扰你多年的C语言疑难杂症特性的C语言进阶课程
从零到写出一个爬虫的Python编程课程
只会语法写不出代码?手把手带你写100个编程真题的编程百练课程
信息学奥赛或C++选手的 必学C++课程
蓝桥杯ACM、信息学奥赛的必学课程:算法竞赛课入门课程
手把手讲解近五年真题的蓝桥杯辅导课程
发表评论 取消回复