[偶数求和]-题解（Java代码）

解题思路: bu zhi dao ru he jie shi

注意事项:

参考代码:

public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while(sc.hasNext()) {
            int num = 0;
            int n = sc.nextInt();
            int m = sc.nextInt();
            int record =n%m;//记录不足的m的位置
            for (int i = 1; i <= n; i++) {
                if (n-i >= record) {
                    if (i%m!=0) {
                        num += average(i);
                    }else if(i%m==0){
                        num += average(i);
                        if (n-i!=record) {
                            System.out.print((num/m)+" ");
                        }else {
                            System.out.print((num/m)+"\n");
                        }
                        num=0;
                    }
                }else {
                    num+=average(i);
                    if (i==n) {
                        record =  n%m==0?1:n%m;
                        System.out.print(num/record+"\n");
                    }
                }
            }
        }
  
    }
    
    public static int average(int n) {
        if (n==1) {
            return 2;
        }
        return 2+average(n-1);
    }