原题链接：[编程入门]自定义函数求一元二次方程
#include<stdio.h>
#include<math.h>
void solve1(double a,double b,double c)
{
printf("x1=%.3lf ",-b/(2*a));
printf("x2=%.3lf ",-b/(2*a));
printf("\n");
}
void solve2(double a,double b,double c)
{
printf("x1=%.3lf+%.3lfi ",-b/(2*a),sqrt(4*a*c-b*b)/(2*a));
printf("x2=%.3lf-%.3lfi",-b/(2*a),sqrt(4*a*c-b*b)/(2*a));
printf("\n");
}
void solve3(double a,double b,double c)
{
printf("x1=%.3lf ",(-b+sqrt(b*b-4*a*c))/(2*a));
printf("x2=%.3lf",(-b-sqrt(b*b-4*a*c))/(2*a));
printf("\n");
}
int main()
{
double a,b,c,d;
scanf("%lf%lf%lf",&a,&b,&c);
d=b*b-4*a*c;
if(d==0)
solve1(a,b,c);
if(d<0)
solve2(a,b,c);
if(d>0)
solve3(a,b,c);
return 0;
}0.0分
30 人评分
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